If it's not what You are looking for type in the equation solver your own equation and let us solve it.
99999=x^2
We move all terms to the left:
99999-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+99999=0
a = -1; b = 0; c = +99999;
Δ = b2-4ac
Δ = 02-4·(-1)·99999
Δ = 399996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{399996}=\sqrt{36*11111}=\sqrt{36}*\sqrt{11111}=6\sqrt{11111}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{11111}}{2*-1}=\frac{0-6\sqrt{11111}}{-2} =-\frac{6\sqrt{11111}}{-2} =-\frac{3\sqrt{11111}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{11111}}{2*-1}=\frac{0+6\sqrt{11111}}{-2} =\frac{6\sqrt{11111}}{-2} =\frac{3\sqrt{11111}}{-1} $
| 15x+3=40-8x | | 4n-8=96 | | 16w+10=-30w+30 | | 5*2+2y=-1 | | 250+x=500+2000 | | 5*1+2y=-1 | | 4/x-10=2x-10/9 | | x²=36 | | 5*2=c | | 35=2x-7 | | 46=2x-7 | | (x-3)(2x-7)=0 | | 2=3.8/x | | r/3+7=15 | | 14(12-4x)=3-x | | -120=1.5q | | 5x-7x+12=36 | | 25x-5=5x-10 | | (3x-1)(5x+3)=0 | | 8y+3=24y-9 | | b/2+8=-4 | | 5x-8/2+4x-8/3=24 | | 2x+1=2x+2. | | 5^1/x=5^6x | | v=4/3*3.14*(20)3 | | 4c-8=12 | | x−6=8 | | F(b)=3b^2+8b-4 | | 4.x=12 | | 10n^2-60-70=0 | | 9y=3+0 | | x+4/5=4+x/10 |